c函数调用过程

C代码:
int fun(int para)
{
    int a=0;
    return 0;
}

void main()
{
    fun(1);
}

汇编代码:

1:
2:
3:      int fun(int para)
4:      {
0040B810     push          ebp                                    ;保护寄存器ebp
0040B811     mov           ebp,esp                             ;此时ebp=esp;此后ebp一般不变
0040B813     sub           esp,44h                              ;44即为40Bytes间隔空间+fun内部变量占有空间,此时fun仅定义一int型变量a,故为4Bytes
0040B816     push          ebx                                      ;保护ebx
0040B817     push          esi                                       ;保护esi
0040B818     push          edi                                       ;保护edi


0040B819     lea           edi,[ebp-44h]                        ;以下四条代码将44Bytes空间置为0CCCCCCCCh
0040B81C     mov           ecx,11h
0040B821     mov           eax,0CCCCCCCCh
0040B826     rep stos      dword ptr [edi]

;以下为自己写的代码

5:        int a=0;
0040B828     mov           dword ptr [ebp-4],0
6:
7:
8:        return 1;
0040B82F     mov           eax,1                                   ;返回值被放入eax
9:      }
0040B831     pop           edi
0040B832     pop           esi
0040B833     pop           ebx
0040B834     mov           esp,ebp
0040B836     pop           ebp
0040B837     ret

10:
11:     void main()
12:     {
0040B790     push          ebp
0040B791     mov           ebp,esp
0040B793     sub           esp,40h
0040B796     push          ebx
0040B797     push          esi
0040B798     push          edi
0040B799     lea           edi,[ebp-40h]
0040B79C     mov           ecx,10h
0040B7A1     mov           eax,0CCCCCCCCh
0040B7A6     rep stos      dword ptr [edi]
13:
14:       fun(1);
0040B7A8     push          1                                                ;参数入栈
0040B7AA     call          @ILT+25(fun) (0040101e)
0040B7AF     add           esp,4                                         ;等效于参数出栈,恢复esp。(此时参数为1 个int型数据,占4Bytes)
15:
16:
17:     }
0040B7B2     pop           edi
0040B7B3     pop           esi
0040B7B4     pop           ebx
0040B7B5     add           esp,40h
0040B7B8     cmp           ebp,esp
0040B7BA     call          __chkesp (004010a0)
0040B7BF     mov           esp,ebp
0040B7C1     pop           ebp
0040B7C2     ret

归纳调用fun的过程为:

(1)参数入栈
(2)调用fun,保护断点,EIP入栈(内部完成,无汇编代码)
(3)保护寄存器ebp
(4)定位新的ebp,此后ebp一般不变
(5)保护ebx,esi,edi
(6)初始化40Bytes间隔空间和fun内部变量

此过程,数据空间变化如下:

(1)参数入栈
       |低地址|...|参数值|...|高地址| ...

                         ^esp指向此                     ^ebp指向某一位置

(2)调用fun,保护断点,EIP入栈(内部完成,无汇编代码)

       |低地址|...|fun返回函数地址|参数值|...|高地址| ...

                         ^esp指向此                                                  ^ebp指向某一位置

(3)保护寄存器ebp

       |低地址|...|ebp入栈值|fun返回函数地址|参数值|...|高地址| ...

                         ^esp指向此                                                       ^ebp指向某一位置

(4)定位新的ebp,此后ebp一般不变

       |低地址|...|ebp入栈值|fun返回函数地址|参数值|...|高地址| ...

                         ^esp和ebp指向此                                                

(5)保护ebx,esi,edi

       |低地址|...|edi入栈值|esi入栈值|ebx入栈值|40Bytes间隔空间|fun内部变量值|ebp入栈值|fun返回函数地址|参数值|...|高地址| ...

                         ^esp指向此                                   ^ebp指向(ebp入栈值)                                      

(6)初始化40Bytes间隔空间和fun内部变量

曾看到一程序:

#include "stdio.h"

int fun()
{
int a=0;
int* p=&a;
p=p+2;
*p=*p+3;

return 0;
}

int main(int argc, char* argv[])
{
int i=1;

fun();
i++;
printf("%d",i);

return 0;
}

下面是其中两段汇编代码:

.......
15:     int i=1;
0040B558     mov           dword ptr [ebp-4],1
16:
17:     fun();
0040B55F   call          @ILT+10(fun) (0040100f)
18:     i++;
0040B564     mov           eax,dword ptr [ebp-4]
0040B567     add           eax,1
0040B56A     mov           dword ptr [ebp-4],eax
...

5:      int a=0;
0040B508     mov           dword ptr [ebp-4],0
6:      int* p=&a;
0040B50F     lea           eax,[ebp-4]
0040B512     mov           dword ptr [ebp-8],eax
7:      p=p+2;
0040B515     mov           ecx,dword ptr [ebp-8]
0040B518     add           ecx,8
0040B51B     mov           dword ptr [ebp-8],ecx
8:      *p=*p+3;
0040B51E     mov           edx,dword ptr [ebp-8]
0040B521     mov           eax,dword ptr [edx]
0040B523     add           eax,3
0040B526     mov           ecx,dword ptr [ebp-8]
0040B529     mov           dword ptr [ecx],eax
9:
10:     return 0;
0040B52B     xor           eax,eax
11:     }
...

其数据空间为:

       |低地址|...|40Bytes间隔空间|p的值|a的值|ebp入栈值|fun返回函数地址|参数值|...|高地址| ...

                                                                               ^ebp指向|ebp入栈值|

由于p=&a,p指向|a的值|,则执行p=p+2后,p指向|fun返回函数地址|

跟踪程序|fun返回函数地址|=0040B564 ,执行的*p=*p+3,|fun返回函数地址|=0040B567   

即fun返回后程序从地址0040B567执行,跳过0040B564 处的代码mov           eax,dword ptr [ebp-4],使得结果i=1,而不是i=2。

posted on 2012-08-28 17:08  山本二十八  阅读(825)  评论(0编辑  收藏  举报

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