根据《算法设计与分析基础》中对归并排序的描述,写了一分C#代码实现。
具体的实现代码如下:
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using System;
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using System.Collections.Generic;
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using System.Text;
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namespace MergeSort
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{
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class Program
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{
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static void Main(string[] args)
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{
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Program p = new Program();
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int[] a = new int[]
{ 4, 2, 1, 6, 3, 6, 0, -5, 1, 1 };
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p.Sort(a);
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for (int i = 0; i < a.Length; i++)
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{
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System.Console.WriteLine(a[i]);
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}
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}
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/**//// <summary>
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/// 利用归并排序按由下到大的顺序排序
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/// </summary>
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/// <param name="toBeSort"></param>
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/// <returns></returns>
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public int[] Sort(int[] toBeSort)
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{
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if (toBeSort.Length == 0)
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{
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throw new Exception("Sort array Error!");
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}
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if (toBeSort.Length > 1)
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{
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int[] part1 = Sort(get1Part(toBeSort));
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int[] part2 = Sort(get2Part(toBeSort));
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merger(part1, part2, toBeSort);
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}
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return toBeSort;
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}
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/**//// <summary>
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/// 将part1和part2按照由小到大的顺序归并到数组toBeSort中
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/// </summary>
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/// <param name="part1"></param>
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/// <param name="part2"></param>
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/// <param name="toBeSort"></param>
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private void merger(int[] part1, int[] part2, int[] toBeSort)
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{
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int index = 0;
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int i1 = 0;
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int i2 = 0;
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while (i1 < part1.Length && i2 < part2.Length)
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{
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if (part1[i1] < part2[i2])
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{
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toBeSort[index] = part1[i1];
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i1++;
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}
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else
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{
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toBeSort[index] = part2[i2];
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i2++;
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}
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index++;
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}
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while (i1 < part1.Length)
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{
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toBeSort[index] = part1[i1];
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index++;
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i1++;
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}
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while (i2 < part2.Length)
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{
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toBeSort[index] = part2[i2];
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index++;
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i2++;
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}
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}
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/**//// <summary>
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/// Get the second part of the array.
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/// </summary>
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/// <param name="toBeSort">The array to be sort.</param>
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/// <returns>The second part of the array.</returns>
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private int[] get2Part(int[] toBeSort)
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{
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int len = toBeSort.Length - toBeSort.Length / 2;
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int[] part2 = new int[len];
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Array.Copy(toBeSort, toBeSort.Length / 2, part2, 0, len);
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return part2;
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}
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/**//// <summary>
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/// Get the first part of the array.
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/// </summary>
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/// <param name="toBeSort">The array to be sort.</param>
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/// <returns>The first part of the array.</returns>
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private int[] get1Part(int[] toBeSort)
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{
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int len = toBeSort.Length / 2;
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int[] part1 = new int[len];
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Array.Copy(toBeSort, part1, len);
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return part1;
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}
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}
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}
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对于分治法的效率分析,有一个通用的公示可以使用:通用分治递推公式。
posted @ 2007-11-12 14:44
逖靖寒 阅读(404)
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