php中使用DOM类读取XML文件

主要功能:php中使用DOM类读取XML文件

设计知识点:

1、XML节点循环读取

2、用iconv()函数实现编码转换,防止中文乱码

holiday.xml文件如下

View Code
<?xml version="1.0" encoding="UTF-8"?>
<daysOff-overTime>
<year>
<yearName>2012</yearName>
<holiday>
<holidayName>元旦</holidayName>
<daysOff>
<from>2012-1-1</from>
<to>2012-1-3</to>
</daysOff>
<overTime>
<day>2011-12-31</day>
</overTime>
</holiday>

<holiday>
<holidayName>春节</holidayName>
<daysOff>
<from>2012-1-22</from>
<to>2012-1-28</to>
</daysOff>
<overTime>
<day>2012-1-21</day>
<day>2012-1-29</day>
</overTime>
</holiday>

<holiday>
<holidayName>清明节</holidayName>
<daysOff>
<from>2012-4-2</from>
<to>2012-4-4</to>
</daysOff>
<overTime>
<day>2012-3-31</day>
<day>2012-4-1</day>
</overTime>
</holiday>

<holiday>
<holidayName>劳动节</holidayName>
<daysOff>
<from>2012-4-29</from>
<to>2012-5-1</to>
</daysOff>
<overTime>
<day>2012-4-28</day>
</overTime>
</holiday>

<holiday>
<holidayName>端午节</holidayName>
<daysOff>
<from>2012-6-22</from>
<to>2012-6-24</to>
</daysOff>
<overTime/>
</holiday>

<holiday>
<holidayName>中秋节、国庆节</holidayName>
<daysOff>
<from>2012-9-30</from>
<to>2012-10-7</to>
</daysOff>
<overTime>
<day>2012-9-26</day>
</overTime>
</holiday>

</year>
</daysOff-overTime>

php代码如下:

<?php
//读取xml文件
$xmlDoc = new DOMDocument();
$xmlDoc->load('http://127.0.0.1/holiday.xml');

//获得该xml文件中的所有年份
$years = $xmlDoc->getElementsByTagName("year");

//对每一个年份进行处理
foreach($years as $year){

//获得具体的年份值
$yearNames = $year->getElementsByTagName("yearName");
$yearName = $yearNames->item(0)->nodeValue;
echo $yearName.'年'.'</br>';

//获得该年份下所有的假日
$holidays = $year->getElementsByTagName("holiday");

//对每一个假日进行处理
foreach($holidays as $holiday){
//获得假日名称
$holidayNames = $holiday->getElementsByTagName("holidayName");
$holidayName = $holidayNames->item(0)->nodeValue;
echo iconv('utf-8','gb2312', $holidayName).': '.'</br>';

//获得假日的具体放假日期
$daysOffs = $holiday->getElementsByTagName("daysOff");
$daysOff = $daysOffs->item(0);
$froms = $daysOff->getElementsByTagName("from");
$from = $froms->item(0)->nodeValue;
$tos = $daysOff->getElementsByTagName("to");
$to = $tos->item(0)->nodeValue;
echo '假期为:'.$from.' 至 '.$to.'</br>';

//获得针对该假日的调休日期
$overTimes = $holiday->getElementsByTagName("overTime");
$overTime = $overTimes->item(0);
$days = $overTime->getElementsByTagName("day");
//通过判断,有调休日期则显示,没有则不显示
if($days->length!=0){
echo '调休日为:';
foreach($days as $day){
echo $day->nodeValue.' ';
}
echo '</br>';
}
echo '</br>';
}
}
?>

输出显示:


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posted on 2011-12-14 11:09  上品物语  阅读(1331)  评论(2编辑  收藏  举报