01 2009 档案

1个式子检测密码强度
摘要: //校验密码级别function checkPassWord(string) { return string.replace(/^(?:(?=.{4})(?=.*([a-z])|.)(?=.*([A-Z])|.)(?=.*(\d)|.)(?=.*(\W)|.).*|.*)$/, "$1$2$3$4").length;};阅读全文
posted @ 2009-01-21 11:50 Ricebug 阅读(53) | 评论 (0) 编辑